(2c-3)(c^2-4c+5)=

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Solution for (2c-3)(c^2-4c+5)= equation: 


Simplifying
(2c + -3)(c2 + -4c + 5) = 0

Reorder the terms:
(-3 + 2c)(c2 + -4c + 5) = 0

Reorder the terms:
(-3 + 2c)(5 + -4c + c2) = 0

Multiply (-3 + 2c) * (5 + -4c + c2)
(-3(5 + -4c + c2) + 2c * (5 + -4c + c2)) = 0
((5 * -3 + -4c * -3 + c2 * -3) + 2c * (5 + -4c + c2)) = 0
((-15 + 12c + -3c2) + 2c * (5 + -4c + c2)) = 0
(-15 + 12c + -3c2 + (5 * 2c + -4c * 2c + c2 * 2c)) = 0
(-15 + 12c + -3c2 + (10c + -8c2 + 2c3)) = 0

Reorder the terms:
(-15 + 12c + 10c + -3c2 + -8c2 + 2c3) = 0

Combine like terms: 12c + 10c = 22c
(-15 + 22c + -3c2 + -8c2 + 2c3) = 0

Combine like terms: -3c2 + -8c2 = -11c2
(-15 + 22c + -11c2 + 2c3) = 0

Solving
-15 + 22c + -11c2 + 2c3 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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